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2q^2-60q=0
a = 2; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·2·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*2}=\frac{0}{4} =0 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*2}=\frac{120}{4} =30 $
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